(4x+42)(2x+25)=714

Solution for (4x+42)(2x+25)=714 equation:

(4x+42)(2x+25)=714

We move all terms to the left:

(4x+42)(2x+25)-(714)=0

We multiply parentheses ..

(+8x^2+100x+84x+1050)-714=0

We get rid of parentheses

8x^2+100x+84x+1050-714=0

We add all the numbers together, and all the variables

8x^2+184x+336=0

a = 8; b = 184; c = +336;
Δ = b2-4ac
Δ = 1842-4·8·336
Δ = 23104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23104}=152$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(184)-152}{2*8}=\frac{-336}{16}
=-21
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(184)+152}{2*8}=\frac{-32}{16}
=-2
$