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2(3x-4)+1=2(6x-3)-9x
We move all terms to the left:
2(3x-4)+1-(2(6x-3)-9x)=0
We multiply parentheses
6x-(2(6x-3)-9x)-8+1=0
We calculate terms in parentheses: -(2(6x-3)-9x), so:We add all the numbers together, and all the variables
2(6x-3)-9x
We add all the numbers together, and all the variables
-9x+2(6x-3)
We multiply parentheses
-9x+12x-6
We add all the numbers together, and all the variables
3x-6
Back to the equation:
-(3x-6)
6x-(3x-6)-7=0
We get rid of parentheses
6x-3x+6-7=0
We add all the numbers together, and all the variables
3x-1=0
We move all terms containing x to the left, all other terms to the right
3x=1
x=1/3
x=1/3
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