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9x(x-8)-2(x+8)=0
We multiply parentheses
9x^2-72x-2x-16=0
We add all the numbers together, and all the variables
9x^2-74x-16=0
a = 9; b = -74; c = -16;
Δ = b2-4ac
Δ = -742-4·9·(-16)
Δ = 6052
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6052}=\sqrt{4*1513}=\sqrt{4}*\sqrt{1513}=2\sqrt{1513}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-2\sqrt{1513}}{2*9}=\frac{74-2\sqrt{1513}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+2\sqrt{1513}}{2*9}=\frac{74+2\sqrt{1513}}{18} $
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