2(3x-3)+7=3(x-7)+8

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Solution for 2(3x-3)+7=3(x-7)+8 equation: 



2(3x-3)+7=3(x-7)+8

We move all terms to the left:

2(3x-3)+7-(3(x-7)+8)=0

We multiply parentheses

6x-(3(x-7)+8)-6+7=0



We calculate terms in parentheses: -(3(x-7)+8), so:

3(x-7)+8

We multiply parentheses

3x-21+8

We add all the numbers together, and all the variables

3x-13

Back to the equation:

-(3x-13)



We add all the numbers together, and all the variables

6x-(3x-13)+1=0

We get rid of parentheses

6x-3x+13+1=0

We add all the numbers together, and all the variables

3x+14=0

We move all terms containing x to the left, all other terms to the right

3x=-14

x=-14/3

x=-4+2/3

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