2(3x-2)-5=2(x-4)+23

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Solution for 2(3x-2)-5=2(x-4)+23 equation: 



2(3x-2)-5=2(x-4)+23

We move all terms to the left:

2(3x-2)-5-(2(x-4)+23)=0

We multiply parentheses

6x-(2(x-4)+23)-4-5=0



We calculate terms in parentheses: -(2(x-4)+23), so:

2(x-4)+23

We multiply parentheses

2x-8+23

We add all the numbers together, and all the variables

2x+15

Back to the equation:

-(2x+15)



We add all the numbers together, and all the variables

6x-(2x+15)-9=0

We get rid of parentheses

6x-2x-15-9=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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