3(2y+1)=23

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Solution for 3(2y+1)=23 equation: 



3(2y+1)=23

We move all terms to the left:

3(2y+1)-(23)=0

We multiply parentheses

6y+3-23=0

We add all the numbers together, and all the variables

6y-20=0

We move all terms containing y to the left, all other terms to the right

6y=20

y=20/6

y=3+1/3

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