2(3x-2)-4=2(x-2)+28

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Solution for 2(3x-2)-4=2(x-2)+28 equation: 



2(3x-2)-4=2(x-2)+28

We move all terms to the left:

2(3x-2)-4-(2(x-2)+28)=0

We multiply parentheses

6x-(2(x-2)+28)-4-4=0



We calculate terms in parentheses: -(2(x-2)+28), so:

2(x-2)+28

We multiply parentheses

2x-4+28

We add all the numbers together, and all the variables

2x+24

Back to the equation:

-(2x+24)



We add all the numbers together, and all the variables

6x-(2x+24)-8=0

We get rid of parentheses

6x-2x-24-8=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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