6a2+23a+21=3

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Solution for 6a2+23a+21=3 equation:



6a^2+23a+21=3
We move all terms to the left:
6a^2+23a+21-(3)=0
We add all the numbers together, and all the variables
6a^2+23a+18=0
a = 6; b = 23; c = +18;
Δ = b2-4ac
Δ = 232-4·6·18
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{97}}{2*6}=\frac{-23-\sqrt{97}}{12} $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{97}}{2*6}=\frac{-23+\sqrt{97}}{12} $

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