2(3x-2)+4=-3x(-5-3x)

Solution for 2(3x-2)+4=-3x(-5-3x) equation:

2(3x-2)+4=-3x(-5-3x)

We move all terms to the left:

2(3x-2)+4-(-3x(-5-3x))=0

We add all the numbers together, and all the variables

2(3x-2)-(-3x(-3x-5))+4=0

We multiply parentheses

6x-(-3x(-3x-5))-4+4=0


We calculate terms in parentheses: -(-3x(-3x-5)), so:

-3x(-3x-5)

We multiply parentheses

9x^2+15x

Back to the equation:

-(9x^2+15x)


We add all the numbers together, and all the variables

6x-(9x^2+15x)=0

We get rid of parentheses

-9x^2+6x-15x=0

We add all the numbers together, and all the variables

-9x^2-9x=0

a = -9; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-9)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-9}=\frac{0}{-18}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-9}=\frac{18}{-18}
=-1
$