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5t-5=2(t-1)-3
We move all terms to the left:
5t-5-(2(t-1)-3)=0
We calculate terms in parentheses: -(2(t-1)-3), so:We get rid of parentheses
2(t-1)-3
We multiply parentheses
2t-2-3
We add all the numbers together, and all the variables
2t-5
Back to the equation:
-(2t-5)
5t-2t+5-5=0
We add all the numbers together, and all the variables
3t=0
t=0/3
t=0
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