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2(3x-1)+2(4x+5)=2(x+4)
We move all terms to the left:
2(3x-1)+2(4x+5)-(2(x+4))=0
We multiply parentheses
6x+8x-(2(x+4))-2+10=0
We calculate terms in parentheses: -(2(x+4)), so:We add all the numbers together, and all the variables
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
14x-(2x+8)+8=0
We get rid of parentheses
14x-2x-8+8=0
We add all the numbers together, and all the variables
12x=0
x=0/12
x=0
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