2+3(4x-4)=6-4(2x+6)

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Solution for 2+3(4x-4)=6-4(2x+6) equation: 



2+3(4x-4)=6-4(2x+6)

We move all terms to the left:

2+3(4x-4)-(6-4(2x+6))=0

We multiply parentheses

12x-(6-4(2x+6))-12+2=0



We calculate terms in parentheses: -(6-4(2x+6)), so:

6-4(2x+6)

determiningTheFunctionDomain
-4(2x+6)+6

We multiply parentheses

-8x-24+6

We add all the numbers together, and all the variables

-8x-18

Back to the equation:

-(-8x-18)



We add all the numbers together, and all the variables

12x-(-8x-18)-10=0

We get rid of parentheses

12x+8x+18-10=0

We add all the numbers together, and all the variables

20x+8=0

We move all terms containing x to the left, all other terms to the right

20x=-8

x=-8/20

x=-2/5

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