2(3x+5)=8(x+1)

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Solution for 2(3x+5)=8(x+1) equation: 



2(3x+5)=8(x+1)

We move all terms to the left:

2(3x+5)-(8(x+1))=0

We multiply parentheses

6x-(8(x+1))+10=0



We calculate terms in parentheses: -(8(x+1)), so:

8(x+1)

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We get rid of parentheses

6x-8x-8+10=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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