(m-12)(8m-2)=0

Solution for (m-12)(8m-2)=0 equation:

(m-12)(8m-2)=0

We multiply parentheses ..

(+8m^2-2m-96m+24)=0

We get rid of parentheses

8m^2-2m-96m+24=0

We add all the numbers together, and all the variables

8m^2-98m+24=0

a = 8; b = -98; c = +24;
Δ = b2-4ac
Δ = -982-4·8·24
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-94}{2*8}=\frac{4}{16}
=1/4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+94}{2*8}=\frac{192}{16}
=12
$