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2(3x+3)=5(x-1)
We move all terms to the left:
2(3x+3)-(5(x-1))=0
We multiply parentheses
6x-(5(x-1))+6=0
We calculate terms in parentheses: -(5(x-1)), so:We get rid of parentheses
5(x-1)
We multiply parentheses
5x-5
Back to the equation:
-(5x-5)
6x-5x+5+6=0
We add all the numbers together, and all the variables
x+11=0
We move all terms containing x to the left, all other terms to the right
x=-11
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