7-3+8(2x-4)=0

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Solution for 7-3+8(2x-4)=0 equation: 



7-3+8(2x-4)=0

We add all the numbers together, and all the variables

8(2x-4)+4=0

We multiply parentheses

16x-32+4=0

We add all the numbers together, and all the variables

16x-28=0

We move all terms containing x to the left, all other terms to the right

16x=28

x=28/16

x=1+3/4

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