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2(3x+3)=3(2x)
We move all terms to the left:
2(3x+3)-(3(2x))=0
determiningTheFunctionDomain 2(3x+3)-32x=0
We add all the numbers together, and all the variables
-32x+2(3x+3)=0
We multiply parentheses
-32x+6x+6=0
We add all the numbers together, and all the variables
-26x+6=0
We move all terms containing x to the left, all other terms to the right
-26x=-6
x=-6/-26
x=3/13
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