2(3x+16)+(2x+8)+(4x-18)+(3x-7)+(2x+25)=180

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Solution for 2(3x+16)+(2x+8)+(4x-18)+(3x-7)+(2x+25)=180 equation:



2(3x+16)+(2x+8)+(4x-18)+(3x-7)+(2x+25)=180
We move all terms to the left:
2(3x+16)+(2x+8)+(4x-18)+(3x-7)+(2x+25)-(180)=0
We multiply parentheses
6x+(2x+8)+(4x-18)+(3x-7)+(2x+25)+32-180=0
We get rid of parentheses
6x+2x+4x+3x+2x+8-18-7+25+32-180=0
We add all the numbers together, and all the variables
17x-140=0
We move all terms containing x to the left, all other terms to the right
17x=140
x=140/17
x=8+4/17

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