(2)/(b-3)=(4)/(b)

Solution for (2)/(b-3)=(4)/(b) equation:

(2)/(b-3)=(4)/(b)

We move all terms to the left:

(2)/(b-3)-((4)/(b))=0


Domain of the equation: (b-3)!=0

We move all terms containing b to the left, all other terms to the right

b!=3

b∈R



Domain of the equation: b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

2/(b-3)-(+4/b)=0

We get rid of parentheses

2/(b-3)-4/b=0

We calculate fractions


2b/(b^2-3b)+(-4b+12)/(b^2-3b)=0

We multiply all the terms by the denominator


2b+(-4b+12)=0

We get rid of parentheses

2b-4b+12=0

We add all the numbers together, and all the variables

-2b+12=0

We move all terms containing b to the left, all other terms to the right

-2b=-12

b=-12/-2

b=+6