2(3x+1)-9x=8(2x+5)

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Solution for 2(3x+1)-9x=8(2x+5) equation: 



2(3x+1)-9x=8(2x+5)

We move all terms to the left:

2(3x+1)-9x-(8(2x+5))=0

We add all the numbers together, and all the variables

-9x+2(3x+1)-(8(2x+5))=0

We multiply parentheses

-9x+6x-(8(2x+5))+2=0



We calculate terms in parentheses: -(8(2x+5)), so:

8(2x+5)

We multiply parentheses

16x+40

Back to the equation:

-(16x+40)



We add all the numbers together, and all the variables

-3x-(16x+40)+2=0

We get rid of parentheses

-3x-16x-40+2=0

We add all the numbers together, and all the variables

-19x-38=0

We move all terms containing x to the left, all other terms to the right

-19x=38

x=38/-19

x=-2

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