(2x+1)+(3x+3)=19

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Solution for (2x+1)+(3x+3)=19 equation: 



(2x+1)+(3x+3)=19

We move all terms to the left:

(2x+1)+(3x+3)-(19)=0

We get rid of parentheses

2x+3x+1+3-19=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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