2(3x+1)-7=1/3(8x-5)

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Solution for 2(3x+1)-7=1/3(8x-5) equation: 



2(3x+1)-7=1/3(8x-5)

We move all terms to the left:

2(3x+1)-7-(1/3(8x-5))=0



Domain of the equation: 3(8x-5))!=0

x∈R



We multiply parentheses

6x-(1/3(8x-5))+2-7=0

We multiply all the terms by the denominator


6x*3(8x-5))-(1+2*3(8x-5))-7*3(8x-5))=0

We add all the numbers together, and all the variables

6x*3(8x-5))-(1+2*3(8x-5))-7*3(8x=0

Wy multiply elements

18x^2(8+18x^2(8=0

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