5t+7+t=3(2t+4)-5

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Solution for 5t+7+t=3(2t+4)-5 equation: 



5t+7+t=3(2t+4)-5

We move all terms to the left:

5t+7+t-(3(2t+4)-5)=0

We add all the numbers together, and all the variables

6t-(3(2t+4)-5)+7=0



We calculate terms in parentheses: -(3(2t+4)-5), so:

3(2t+4)-5

We multiply parentheses

6t+12-5

We add all the numbers together, and all the variables

6t+7

Back to the equation:

-(6t+7)



We get rid of parentheses

6t-6t-7+7=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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