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2(3x+1)-3(6-2x)=20
We move all terms to the left:
2(3x+1)-3(6-2x)-(20)=0
We add all the numbers together, and all the variables
2(3x+1)-3(-2x+6)-20=0
We multiply parentheses
6x+6x+2-18-20=0
We add all the numbers together, and all the variables
12x-36=0
We move all terms containing x to the left, all other terms to the right
12x=36
x=36/12
x=3
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