2(3x+1)+x-3(2x+1)=x+4(x-1)-4(x+3)

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Solution for 2(3x+1)+x-3(2x+1)=x+4(x-1)-4(x+3) equation: 



2(3x+1)+x-3(2x+1)=x+4(x-1)-4(x+3)

We move all terms to the left:

2(3x+1)+x-3(2x+1)-(x+4(x-1)-4(x+3))=0

We add all the numbers together, and all the variables

x+2(3x+1)-3(2x+1)-(x+4(x-1)-4(x+3))=0

We multiply parentheses

x+6x-6x-(x+4(x-1)-4(x+3))+2-3=0



We calculate terms in parentheses: -(x+4(x-1)-4(x+3)), so:

x+4(x-1)-4(x+3)

We multiply parentheses

x+4x-4x-4-12

We add all the numbers together, and all the variables

x-16

Back to the equation:

-(x-16)



We add all the numbers together, and all the variables

x-(x-16)-1=0

We get rid of parentheses

x-x+16-1=0

We add all the numbers together, and all the variables

15!=0

There is no solution for this equation

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