6x2-11x+3=0

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Solution for 6x2-11x+3=0 equation:



6x^2-11x+3=0
a = 6; b = -11; c = +3;
Δ = b2-4ac
Δ = -112-4·6·3
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-7}{2*6}=\frac{4}{12} =1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+7}{2*6}=\frac{18}{12} =1+1/2 $

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