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2(3x+1)+5x-3=-2(-3x+5)
We move all terms to the left:
2(3x+1)+5x-3-(-2(-3x+5))=0
We add all the numbers together, and all the variables
5x+2(3x+1)-(-2(-3x+5))-3=0
We multiply parentheses
5x+6x-(-2(-3x+5))+2-3=0
We calculate terms in parentheses: -(-2(-3x+5)), so:We add all the numbers together, and all the variables
-2(-3x+5)
We multiply parentheses
6x-10
Back to the equation:
-(6x-10)
11x-(6x-10)-1=0
We get rid of parentheses
11x-6x+10-1=0
We add all the numbers together, and all the variables
5x+9=0
We move all terms containing x to the left, all other terms to the right
5x=-9
x=-9/5
x=-1+4/5
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