3(k-4)=8k+28

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Solution for 3(k-4)=8k+28 equation: 



3(k-4)=8k+28

We move all terms to the left:

3(k-4)-(8k+28)=0

We multiply parentheses

3k-(8k+28)-12=0

We get rid of parentheses

3k-8k-28-12=0

We add all the numbers together, and all the variables

-5k-40=0

We move all terms containing k to the left, all other terms to the right

-5k=40

k=40/-5

k=-8

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