2(3x*1x)+2(3x*2x)+2(1x*2x)=88

Solution for 2(3x*1x)+2(3x*2x)+2(1x*2x)=88 equation:

2(3x*1x)+2(3x*2x)+2(1x*2x)=88

We move all terms to the left:

2(3x*1x)+2(3x*2x)+2(1x*2x)-(88)=0

We add all the numbers together, and all the variables

2(+3x*1x)+2(+3x*2x)+2(+1x*2x)-88=0

We multiply parentheses

6x^2+12x^2+4x^2-88=0

We add all the numbers together, and all the variables

22x^2-88=0

a = 22; b = 0; c = -88;
Δ = b2-4ac
Δ = 02-4·22·(-88)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*22}=\frac{-88}{44}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*22}=\frac{88}{44}
=2
$