-3(-6x+1)-2=2(x-4)-2

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Solution for -3(-6x+1)-2=2(x-4)-2 equation: 



-3(-6x+1)-2=2(x-4)-2

We move all terms to the left:

-3(-6x+1)-2-(2(x-4)-2)=0

We multiply parentheses

18x-(2(x-4)-2)-3-2=0



We calculate terms in parentheses: -(2(x-4)-2), so:

2(x-4)-2

We multiply parentheses

2x-8-2

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

18x-(2x-10)-5=0

We get rid of parentheses

18x-2x+10-5=0

We add all the numbers together, and all the variables

16x+5=0

We move all terms containing x to the left, all other terms to the right

16x=-5

x=-5/16

x=-5/16

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