2(3u+4)=-4(2u+2)

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Solution for 2(3u+4)=-4(2u+2) equation: 



2(3u+4)=-4(2u+2)

We move all terms to the left:

2(3u+4)-(-4(2u+2))=0

We multiply parentheses

6u-(-4(2u+2))+8=0



We calculate terms in parentheses: -(-4(2u+2)), so:

-4(2u+2)

We multiply parentheses

-8u-8

Back to the equation:

-(-8u-8)



We get rid of parentheses

6u+8u+8+8=0

We add all the numbers together, and all the variables

14u+16=0

We move all terms containing u to the left, all other terms to the right

14u=-16

u=-16/14

u=-1+1/7

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