-2j-(5j+2)=-(3j-1)

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Solution for -2j-(5j+2)=-(3j-1) equation: 



-2j-(5j+2)=-(3j-1)

We move all terms to the left:

-2j-(5j+2)-(-(3j-1))=0

We get rid of parentheses

-2j-5j-(-(3j-1))-2=0



We calculate terms in parentheses: -(-(3j-1)), so:

-(3j-1)

We get rid of parentheses

-3j+1

Back to the equation:

-(-3j+1)



We add all the numbers together, and all the variables

-7j-(-3j+1)-2=0

We get rid of parentheses

-7j+3j-1-2=0

We add all the numbers together, and all the variables

-4j-3=0

We move all terms containing j to the left, all other terms to the right

-4j=3

j=3/-4

j=-3/4

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