2(3t+1)-5=t-(-t+2)

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Solution for 2(3t+1)-5=t-(-t+2) equation: 



2(3t+1)-5=t-(-t+2)

We move all terms to the left:

2(3t+1)-5-(t-(-t+2))=0

We add all the numbers together, and all the variables

2(3t+1)-(t-(-1t+2))-5=0

We multiply parentheses

6t-(t-(-1t+2))+2-5=0



We calculate terms in parentheses: -(t-(-1t+2)), so:

t-(-1t+2)

We get rid of parentheses

t+1t-2

We add all the numbers together, and all the variables

2t-2

Back to the equation:

-(2t-2)



We add all the numbers together, and all the variables

6t-(2t-2)-3=0

We get rid of parentheses

6t-2t+2-3=0

We add all the numbers together, and all the variables

4t-1=0

We move all terms containing t to the left, all other terms to the right

4t=1

t=1/4

t=1/4

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