2(3m+5)+4(2m+1)=20m-19

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Solution for 2(3m+5)+4(2m+1)=20m-19 equation: 



2(3m+5)+4(2m+1)=20m-19

We move all terms to the left:

2(3m+5)+4(2m+1)-(20m-19)=0

We multiply parentheses

6m+8m-(20m-19)+10+4=0

We get rid of parentheses

6m+8m-20m+19+10+4=0

We add all the numbers together, and all the variables

-6m+33=0

We move all terms containing m to the left, all other terms to the right

-6m=-33

m=-33/-6

m=5+1/2

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