3x2+10+6+12x+5x+2x2=

Solution for 3x2+10+6+12x+5x+2x2= equation:

3x^2+10+6+12x+5x+2x^2=

We move all terms to the left:

3x^2+10+6+12x+5x+2x^2-()=0

We add all the numbers together, and all the variables

5x^2+17x=0

a = 5; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·5·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*5}=\frac{-34}{10}
=-3+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*5}=\frac{0}{10}
=0
$