2(3k+2)=4k+24

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Solution for 2(3k+2)=4k+24 equation: 



2(3k+2)=4k+24

We move all terms to the left:

2(3k+2)-(4k+24)=0

We multiply parentheses

6k-(4k+24)+4=0

We get rid of parentheses

6k-4k-24+4=0

We add all the numbers together, and all the variables

2k-20=0

We move all terms containing k to the left, all other terms to the right

2k=20

k=20/2

k=10

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