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2(3h-2)-1=2(h-1)+1
We move all terms to the left:
2(3h-2)-1-(2(h-1)+1)=0
We multiply parentheses
6h-(2(h-1)+1)-4-1=0
We calculate terms in parentheses: -(2(h-1)+1), so:We add all the numbers together, and all the variables
2(h-1)+1
We multiply parentheses
2h-2+1
We add all the numbers together, and all the variables
2h-1
Back to the equation:
-(2h-1)
6h-(2h-1)-5=0
We get rid of parentheses
6h-2h+1-5=0
We add all the numbers together, and all the variables
4h-4=0
We move all terms containing h to the left, all other terms to the right
4h=4
h=4/4
h=1
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