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(0.5w+0.4)(w+0.6)=0
We multiply parentheses ..
(+0w^2+0w+0.4w+0.24)=0
We get rid of parentheses
0w^2+0w+0.4w+0.24=0
We add all the numbers together, and all the variables
w^2+1.4w+0.24=0
a = 1; b = 1.4; c = +0.24;
Δ = b2-4ac
Δ = 1.42-4·1·0.24
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.4)-\sqrt{1}}{2*1}=\frac{-1.4-\sqrt{1}}{2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.4)+\sqrt{1}}{2*1}=\frac{-1.4+\sqrt{1}}{2} $
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