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2(3g+1)+2=1/2(12g+8)
We move all terms to the left:
2(3g+1)+2-(1/2(12g+8))=0
Domain of the equation: 2(12g+8))!=0We multiply parentheses
g∈R
6g-(1/2(12g+8))+2+2=0
We multiply all the terms by the denominator
6g*2(12g+8))-(1+2*2(12g+8))+2*2(12g+8))=0
We add all the numbers together, and all the variables
6g*2(12g+8))-(1+2*2(12g+8))+2*2(12g=0
Wy multiply elements
12g^2(1+8g^2(1=0
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