2(3f-1)+3(f-5)=f+11

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Solution for 2(3f-1)+3(f-5)=f+11 equation: 



2(3f-1)+3(f-5)=f+11

We move all terms to the left:

2(3f-1)+3(f-5)-(f+11)=0

We multiply parentheses

6f+3f-(f+11)-2-15=0

We get rid of parentheses

6f+3f-f-11-2-15=0

We add all the numbers together, and all the variables

8f-28=0

We move all terms containing f to the left, all other terms to the right

8f=28

f=28/8

f=3+1/2

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