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3(1-2x)+10=2(3x+1)
We move all terms to the left:
3(1-2x)+10-(2(3x+1))=0
We add all the numbers together, and all the variables
3(-2x+1)-(2(3x+1))+10=0
We multiply parentheses
-6x-(2(3x+1))+3+10=0
We calculate terms in parentheses: -(2(3x+1)), so:We add all the numbers together, and all the variables
2(3x+1)
We multiply parentheses
6x+2
Back to the equation:
-(6x+2)
-6x-(6x+2)+13=0
We get rid of parentheses
-6x-6x-2+13=0
We add all the numbers together, and all the variables
-12x+11=0
We move all terms containing x to the left, all other terms to the right
-12x=-11
x=-11/-12
x=11/12
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