2(3d-5)-5(2d+3)=11

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Solution for 2(3d-5)-5(2d+3)=11 equation: 



2(3d-5)-5(2d+3)=11

We move all terms to the left:

2(3d-5)-5(2d+3)-(11)=0

We multiply parentheses

6d-10d-10-15-11=0

We add all the numbers together, and all the variables

-4d-36=0

We move all terms containing d to the left, all other terms to the right

-4d=36

d=36/-4

d=-9

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