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3(2x+1)-(6-2x)=13
We move all terms to the left:
3(2x+1)-(6-2x)-(13)=0
We add all the numbers together, and all the variables
3(2x+1)-(-2x+6)-13=0
We multiply parentheses
6x-(-2x+6)+3-13=0
We get rid of parentheses
6x+2x-6+3-13=0
We add all the numbers together, and all the variables
8x-16=0
We move all terms containing x to the left, all other terms to the right
8x=16
x=16/8
x=2
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