2(3c-6)-8=c+15

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Solution for 2(3c-6)-8=c+15 equation: 



2(3c-6)-8=c+15

We move all terms to the left:

2(3c-6)-8-(c+15)=0

We multiply parentheses

6c-(c+15)-12-8=0

We get rid of parentheses

6c-c-15-12-8=0

We add all the numbers together, and all the variables

5c-35=0

We move all terms containing c to the left, all other terms to the right

5c=35

c=35/5

c=7

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