9/(x-3)=(3x)/(x-3)

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Solution for 9/(x-3)=(3x)/(x-3) equation: 



9/(x-3)=(3x)/(x-3)

We move all terms to the left:

9/(x-3)-((3x)/(x-3))=0



Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R





Domain of the equation: (x-3))!=0

x∈R



We calculate fractions


9x/((x-3)*(x-3)))+(-(3x*(x-3))/((x-3)*(x-3)))=0



We calculate terms in parentheses: -(3x*(x-3))/((x-3)*(x-3))), so:

3x*(x-3))/((x-3)*(x-3))

We multiply all the terms by the denominator


3x*(x-3))

We multiply parentheses

3x^2-9x^2

We add all the numbers together, and all the variables

-6x^2

Back to the equation:

-(-6x^2)



We get rid of parentheses

6x^2+9x/((x-3)*(x-3)))+(=0

We multiply all the terms by the denominator


6x^2*((x-3)*(x-3)))+(+9x=0

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