2(3c-2)=4c+10

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Solution for 2(3c-2)=4c+10 equation: 



2(3c-2)=4c+10

We move all terms to the left:

2(3c-2)-(4c+10)=0

We multiply parentheses

6c-(4c+10)-4=0

We get rid of parentheses

6c-4c-10-4=0

We add all the numbers together, and all the variables

2c-14=0

We move all terms containing c to the left, all other terms to the right

2c=14

c=14/2

c=7

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