-3=7/3(-2)+b

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Solution for -3=7/3(-2)+b equation: 



-3=7/3(-2)+b

We move all terms to the left:

-3-(7/3(-2)+b)=0



Domain of the equation: 3(-2)+b)!=0

b∈R



We multiply all the terms by the denominator


-(7-3*3(-2)+b)=0



We calculate terms in parentheses: -(7-3*3(-2)+b), so:

7-3*3(-2)+b

determiningTheFunctionDomain
b+7-3*3(-2)

We add all the numbers together, and all the variables

b+25

Back to the equation:

-(b+25)



We get rid of parentheses

-b-25=0

We add all the numbers together, and all the variables

-1b-25=0

We move all terms containing b to the left, all other terms to the right

-b=25

b=25/-1

b=-25

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