2(3c+15)+4c=100

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Solution for 2(3c+15)+4c=100 equation: 



2(3c+15)+4c=100

We move all terms to the left:

2(3c+15)+4c-(100)=0

We add all the numbers together, and all the variables

4c+2(3c+15)-100=0

We multiply parentheses

4c+6c+30-100=0

We add all the numbers together, and all the variables

10c-70=0

We move all terms containing c to the left, all other terms to the right

10c=70

c=70/10

c=7

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