2(x-26)(x+4)=0

Solution for 2(x-26)(x+4)=0 equation:

2(x-26)(x+4)=0

We multiply parentheses ..

2(+x^2+4x-26x-104)=0

We multiply parentheses

2x^2+8x-52x-208=0

We add all the numbers together, and all the variables

2x^2-44x-208=0

a = 2; b = -44; c = -208;
Δ = b2-4ac
Δ = -442-4·2·(-208)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-60}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+60}{2*2}=\frac{104}{4}
=26
$