2(3b-)=40

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Solution for 2(3b-)=40 equation: 



2(3b-)=40

We move all terms to the left:

2(3b-)-(40)=0

We add all the numbers together, and all the variables

2(+3b)-40=0

We multiply parentheses

6b-40=0

We move all terms containing b to the left, all other terms to the right

6b=40

b=40/6

b=6+2/3

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